F(X)=AX*2+BX+C

TURN STANDARD FORM TO VERTEX FORM F(X)=A(X-H)*2+K

THE LINE THAT PASSES THROUGH THE AXIS OF SYMMETRY

X*2-6X+9=25

(X-3)*2=25

FIND THE SQUARE ROOT OF (X-3)*2 AND THE SQUARE ROOT OF 25

X-3=5

X=3+OR-5

X=8 X=-2

EX. 8X*2+4X*2+2X

STEP 1. IDENTIFY THE GCF OF THE POLYNOMIAL

STEP 2. DIVIDE THE GCF OUT OF EVERY TERM OF THE POLYMOMIAL

BESURE THE COEFFICIENT OF THE HIGHEST POWER IS 1. EX. X=X*2+8X-4=0

MOVE THE CONSTANT RIGHT. X*2+8X=4

PREPARE THE NEEDED VALUE X*2+8X_=4+_

FIND THE NEEDED VALUE X*2+8X+16=4+16

FACTOR THE PERFECT SQUAR TRINOMIAL. (X+4)(X+4)=20............(X+4)=20

TAKE THE SQUARE ROOT OF EACH SIDE AND SOLVE